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10n^2-9n-4=0
a = 10; b = -9; c = -4;
Δ = b2-4ac
Δ = -92-4·10·(-4)
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{241}}{2*10}=\frac{9-\sqrt{241}}{20} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{241}}{2*10}=\frac{9+\sqrt{241}}{20} $
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